Story problem

If 2 kayaks leave from Bothell at 11:30 on Memorial Day and are travelling up current, maintaining a cruising speed of 2 knots, a locomotive leaves Kansas City heading to Tulsa at 11:45 travelling at 45 mph during high tide, and 3 big canoes leave from Redmond at noon, travelling down current at 3 knots, when will they meet? Before you answer, allow me to introduce a few variables:

-Careful documentation throughout history has proven that any shelter that has ever included the term 'single-wide' in its description is 900% more likely to be subject to big wind. If the 2 kayaks are exposed to an area that fits this description for 5 minutes, how much will they be slowed?

-If there is any part of the general plan that involves group parking, 3 or more cars, a 'shuttle', and it is daylight savings time, how does this factor into the problem?

-If 1 kayaker tries to the lead the other down a 'short cut', or under hanging trees, or is easily distracted by shiny objects, or has to worry about the other kayaker ramming into and sinking him on purpose, how much additional time is lost?

-If no one is riding on that locomotive travelling from Kansas City to Tulsa, did it ever really leave? And can you blame people for not getting on the train?

-Last, paddling law tells us that canoeists=single paddle. Single paddle=giant spoon. Giant spoon=soup. Soup=sick. Sick=bed. Bed=pillows. Pillows=soft. By using the transitive property, we have now proved that canoeists are soft. Don't believe me? Click the picture below and check out the form on the bow.

Send you answers, along with a kevlar flex-core Wenonah Voyager solo canoe in color sand with black aluminum trim, to admin at smalladventure dot com. Or put it in the comments. But don't forget to send the boat.